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1. A company has five machines (1 lathe, 2 mills and 2 drills) arranged sequentially to produce a batch of 200 parts. The fol
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Answer #1

(a) The manufacturing lead time for conventional set up of machines

set up time for each step + work cycle time x number of units + delay for each machine

Case I - If the batch of 200 parts is produced in one go.

Set up time = 6.5 hours.

Processing time = 200 x ( 15+27+12+7+9) = 200x70 = 14000 min = 14000/60 hours = 233.33 hours

Delay = 5x10 =50 hours

Total manufacturing lead time = 6.5+233.33+50 = 289.83 hours

Case II -If the work is done in 2 batches of 100 each. time taken to produce each batch

Set up time = 6.5 hours

Processing time = 116.66 hours

Delay time = 50 hours

Total time = 173.16 hours to produce each batch

(b) Manu. Lead time for single machine when 200 parts are produced in one go

2+233.33 + 10 = 245.33 hours

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please answer this i need it asap ill make sure to rate and give thumbs up! 1. A company has five machines (1 lathe, 2 mills and 2 drills) arranged sequentially to produce a batch of 200 parts. Th...
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