Solution:-
2)
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: u = 60
Alternative hypothesis: u 60
Note that these hypotheses constitute a two-tailed test.
Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method is a one-sample t-test.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = s / sqrt(n)
S.E = 4.0634
DF = n - 1
D.F = 5
t = (x - u) / SE
t = - 0.574
where s is the standard deviation of the sample, x is the sample mean, u is the hypothesized population mean, and n is the sample size.
Since we have a two-tailed test, the P-value is the probability that the t statistic having 5 degrees of freedom is less than -0.574 or greater than 0.574.
Thus, the P-value = 0.591.
Interpret results. Since the P-value (0.591) is greater than the significance level (0.05), we cannot reject the null hypothesis.
From the above test we do not have sufficient evidence in the favor of the claim that its products weight 60 gram in average.
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