Homework Answers
The reaction is:
CuSO4. 5 H2O + 2 KIO3 = Cu(IO3)2 + 5 H2O + K2SO4
So, mole ratio of CuSO4. 5 H2O : KIO3 is 1 :2
Moles of CuSO4. 5 H2O = Mass/ Molar mass = 0.650 g / ( 249.67 g / mole) = 0.0026 mole
So, mole sof KIO3 needed for the precipitation = 0.0026 * 2 = 0.0052 mole
Mass of KIO3 needed = Moles * Molar mass = 0.0052 mole * 214 g / mole = 1.11 g
Answer is : 1.11 g
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