Question

A random sample has a mean of 16.5 and variance of 16, with n = 35 . The null hypothesis Ho : ? = 20 is to be tested against the alternative hypothesis Ha : ? ? 20 with 99% confidence level. What is the value of the test statistics ? Write your answer with 2 decimal places.

Answer 1

Solution :

Given that,

$\bar x$ = 16.5

s² = 16

s = 4

$\mu$ = 38 and n = 35

t = ( $\bar x$ - $\mu$ ) / s / $\sqrt$ n = (16.5 - 20) / 4 / $\sqrt$ 35 = -5.18

Test statistic = -5.18