given
n = 22 % (or) 0.22
W = 18000 J
T1 = 810 C
= 810 + 273
= 1083 K
a) we know, n = W/Qin
==> Qin = W/n
= 18000/0.22
= 81818 J <<<<<<<---------------Answer
b) Q_out = Qin - W
= 81818 - 18000
= 63818 J <<<<<<<---------------Answer
c) use, n = 1 - T2/T1
T2/T1 = 1 - n
T2 = T1*(1 - n)
= 1083*(1 - 0.22)
= 845 k
= 845 - 273
= 572 degrees Celsius <<<<<<<---------------Answer
6 Example 15-8, An engine has efficiency of 22% and produces 18000 J mechanical work at...
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