Question

enthalpy There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: Cac (s) + 2H,O(g) + CH (9) + Ca(OH),(s) In the second step, acetylene, carbon dioxide and water react to form acrylic acid 6C,H,9) + 3 CO (9) + 4H,O(9) 5CH,CHCO,H) AH=132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions, Round your answer to the nearest kJ. $ ?

Answer 1

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Apes Wo will nead to add the o Seadtion dngdh en to eome up with an ovenall eation eion fon he o steps Cano Cala ta) t 20 1)- Gt tCa Con) AH--414KJ 5CH CH Co M) DH132 K3 acelylere on Are faodet side One Dhe aveactont side in Aho second euabion ndsix On we have do mliyhe h ole iast eartion oith Ca0x6Cale to) +R0 ) Ga g)t6Ca Cotte) DH24 4 5 CH CH CoH ) H13K3 SCH,H C0t6Ca Coe) 6 Cals t16H2o (0)+ 300g) DH-2 352KJ This anount a onehq is given d fonthe Smales of asid -2352KJ 4704 RJ 0kT2019/11/12 0

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