ZuoTi.Pro
Question

Dimethyl ether, a useful organic solvent, is prepared in two steps. In the first step, carbon dioxide and hydrogen react to form methanol and water: In the second step, methanol reacts to form dimethyl ether and water: Calculate the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and hydrogen from these reactions. Round your answer to the nearest kJ kJ

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Target eqn: 2CO2 (g) + 6H2 (g) → CH3OCH, (g)+3H2O(1): AH=? ) CO2 (g) + 3H2(g)→ CH3OH(l)+H2O(1): ΔΗ,=-131kT multiply the equation with 2 2CO2 (g) + 6H2(g)-> 2CH30E(l)+2H2O(1): am,-2(-131kT)--262kT add the 2 equati on to get the target equation 2cO2 (g) + 6H2(8) ->20%eH(0+2H20(1): H,--262 kJ =-254 kJ

0 0
Add a comment
Know the answer?
Add Answer to:
Dimethyl ether, a useful organic solvent, is prepared in two steps. In the first step, carbon...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Dimethyl ether, a useful organic solvent, is prepared in two steps. In the first step, carbon...

    Dimethyl ether, a useful organic solvent, is prepared in two steps. In the first step, carbon dioxide and hydrogen react to form methanol and water: CO2(g) + 3H2(g) → CH3OH (l) + H2O(l) =ΔH−131.kJ In the second step, methanol reacts to form dimethyl ether and water: 2CH3OH (l) → CH3OCH3(g) + H2O (l) =ΔH8.kJ Calculate the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and hydrogen from these reactions. Round your answer...

  • Using Hess's Law to calculate net reaction enthalpy Dimethycurier, a useful organic solvent, is prepared in...

    Using Hess's Law to calculate net reaction enthalpy Dimethycurier, a useful organic solvent, is prepared in two steps. In the first step, carbon dioxide and hydrogen react to form methanol and water: CO2(g) + 3H2(9) - CH2OH(1) + H2O(1) AH-131. J In the second step, methanol reacts to form dimethyl ether and water: 2 CH,OH(1) - CH,OCH,(9) + H,00 AH8. kJ Calculate the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and...

  • There are two steps in the usual industrial preparation of acrylic acid, the water react to...

    There are two steps in the usual industrial preparation of acrylic acid, the water react to form acetylene and calcium hydroxide: immediate precursor of several useful plastics. In the first step, calcium carbide and Cac,(s)+2H,019) CHo)+Ca(o)(s)414. In the second step, acetylene, carbon dioxide and water react to form acrylic acid Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions Round your answer to the...

  • enthalpy There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor...

    enthalpy There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: Cac (s) + 2H,O(g) + CH (9) + Ca(OH),(s) In the second step, acetylene, carbon dioxide and water react to form acrylic acid 6C,H,9) + 3 CO (9) + 4H,O(9) 5CH,CHCO,H) AH=132. kJ Calculate the net change in enthalpy for the formation of one mole...

  • There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of...

    There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: CaC (s) + 2 H2O(g) - CH (9) + Ca(OH),(s) AH -414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6 C H (9) + 3 CO2(9) + 4H2O(g) - SCH,CHCO,H) AH-132. kJ Calculate the net change in enthalpy...

  • 3 % 10 13 There are two steps in the usual industrial preparation of acrylic and...

    3 % 10 13 There are two steps in the usual industrial preparation of acrylic and the immediate precursor of several useful plastics in the first seep, calcium carbidean water react to form acetylene and calcium hydroxide: CoC (8) + 2H0(9) -- C.H.(0) + Ca(OH),(s) AH--141 In the second step, acetylene, carbon dioxide and water react to form acrylic acid 6CH (2) + 300,(9) + 4H,019) -- SCH,CHCO,H() AH-132.00 Calculate the net change in enthalpy for the formation of one...

  • Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus...

    Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. In the first step, nitrogen and hydrogen react to form ammonia: N (0) + 3H (9) 2 NH,(9) AH = -92. kJ In the second step, ammonia and oxygen react to form nitric acid and water: NH (g) + 20 (g) – INO,g) + H20() AH -330, RJ Calculate the net change in enthalpy for the formation of...

  • Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus...

    Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. In the first step, nitrogen and hydrogen react to form ammonia: N219)+3 H2(9)2 NH,(9) AH-92. kJ In the second step, ammonia and oxygen react to form nitric acid and water: NH3(9)+ 20,(9)HNO3(g)+ H,O(g) AH-330. kJ Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions....

  • Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the...

    Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react to form ammonia: N2(9) + 3 H (9) 2NH (9) AH = -92. kJ In the second step, ammonia and oxygen react to form nitric oxide and water: 4 NH (9) + 50,(9) 4 NO(9) + 6H2O(9) AH = -905. kJ Calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen,...

  • Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus...

    Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. In the first step, nitrogen and hydrogen react to form ammonia: N2(g) + 3H2(g) 2NH3(g) H = -92.kJ In the second step, ammonia and oxygen react to form nitric acid and water: NH3(g) + 2O2(g) HNO3(g) + H20 (g) H=-330.kJ Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT