Question

3 % 10 13 There are two steps in the usual industrial preparation of acrylic and the immediate precursor of several useful plastics in the first seep, calcium carbidean water react to form acetylene and calcium hydroxide: CoC (8) + 2H0(9) -- C.H.(0) + Ca(OH),(s) AH--141 In the second step, acetylene, carbon dioxide and water react to form acrylic acid 6CH (2) + 300,(9) + 4H,019) -- SCH,CHCO,H() AH-132.00 Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions Round your answer to the nearest

Answer 1

Multiply the first equation with 6 and then add to second equation.

6cat, ts) + hво (6) { (c) a c tete h (4) Аул. Вк (- 4 ч) lет в , м, 6) 13 се, 4) - + 4H206) 501. CHCOH (5) Ан: 13 - 1 Сct, (5) + 3 co, C6) + 16 ць (4) 5-4 го, н) 6 са го и, 15) Дне - Uх ЧІЧ k. t13. «Т г - щ€чеј 1 13 кг -235. «Т 5 mol acrylic and с 13Sky for Imol acrylic - 135 LT чә0- 4 к1 [rtəој ел O

-470 kJ