Vmax of an enzyme-catalyzed reaction is A. the rate observed when the enzyme active sites are...
Vmax of an enzyme-catalyzed reaction is
A. the rate observed when the enzyme active sites are saturated with substrate
B. independent of the amount of enzyme present
C. the rate observed at the highest substrate concentration that can be experimentally obtained
D. the initial rate observed at very low substrate concentrations
Homework Answers
Option A is right answer.
As the concentration of substrate increases enzyme becomes saturated with substrate at Vmax which is maximum rate of reaction.
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Vmax of an enzyme-catalyzed reaction is
A. the rate observed when the enzyme active sites are...
Under what circumstances does an enzyme catalyzed reaction rate resemble a non-enzyme catalyzed reaction? At very...
Under what circumstances does an enzyme catalyzed reaction rate resemble a non-enzyme catalyzed reaction? At very low concentrations of substrate (Km is greater than S) the Michaelis-Menton equation can be simplified to? At very high concentrations of substrate, the Michaelis-Menton equation can be simplified to? How do you determine the initial rate of reaction
2-In an enzyme-catalyzed reaction, the rate of the reaction depends on which of the following at...
2-In an enzyme-catalyzed reaction, the rate of the reaction depends on which of the following at very low substrate concentrations? Select one: Neither enzyme concentration nor substrate concentration Enzyme concentration but not substrate concentration Substrate concentration but not enzyme concentration Both substrate concentration and enzyme concentration
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does...
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does the reaction rate actually get to Vmax? Determine how high (i.e. how many times Km) the substrate concentration must be for the reaction rate to be: a. 98% Vmax (show your work) (2) b. 99% Vmax (answer only) (1) c. 99.9% Vmax (answer only) (1)
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does...
At high (saturating) substrate concentrations, the rate of an enzyme-catalyzed reaction approaches Vmax. How close does the reaction rate actually get to Vmax? Determine how high (i.e. how many times Km) the substrate concentration must be for the reaction rate to be: a. 98% Vmax (show your work) (2) b. 99% Vmax (answer only) (1) c. 99.9% Vmax (answer only) (1)
What is the rate of an enzyme catalyzed reaction if the Vmax is 100µmol S→P/min and...
What is the rate of an enzyme catalyzed reaction if the Vmax is 100µmol S→P/min and the Km is 7 mM and the substrate concentration is 11mM? Is the enzyme working at Vmax? What if the substrate concentration is raised to 25mM?
The rate of an enzyme-catalyzed reaction initially increases with an increase in the substrate concentration, but...
The rate of an enzyme-catalyzed reaction initially increases with an increase in the substrate concentration, but eventually reaches a maximum value, even though the concentration of substrate continues to increase. Which of the following best explains why? O As substrate concentration increases, the substrates preferentially bind with each other instead of the active site of the enzyme, and no additional catalysis occurs. As substrate concentration increases, the active sites of all the enzyme molecules become occupied with substrate molecules, and...
Need help with number 13! I already asked about number 12. The inverse velocity and inverse substrate concentration relationship for an enzyme-catalyzed reaction is given below V Vmax Vmax S For the...
Need help with number 13! I already asked about number
12. The inverse velocity and inverse substrate concentration relationship for an enzyme-catalyzed reaction is given below V Vmax Vmax S For the hydration of CO2 catalyzed by carbonic anhydrase, it was determined experimentally that (dm s mol 4023.9+ 39.934 at a total enzyme IS] concentration of 2.32 × 10-y mol-dm- What is the value of the Michaelis constant KM for this enzymatic reaction? (B). 9.92x103 mol dm3 (D). 100.8 mol...
3. The Michaelis-Menten Graph also shows the theoretical maximum rate of the enzyme (Vmax), the point...
3. The Michaelis-Menten Graph also shows the theoretical maximum rate of the enzyme (Vmax), the point where the enzyme is working at its maximum rate (Vmax/2), and amount of substrate needed to bind half of the active sites (Km). Label these points on the graph. Vmax represents: Vm Vmax/2 represents: Reaction velocity v Vmax 2 Km represents: Kim Substrate concentration (5)
a. An enzyme has a Vmax of 100 umol/min and a Km of 40 uM. When...
a. An enzyme has a Vmax of 100 umol/min and a Km of 40 uM. When substrate concentration is 40 uM what is the initial reaction rate? b. An enzyme with a Vmax of 100 umol/minute and a Km of 10 uM was reacted with a irreversible active site specific inhibitor. After reaction with the inhibitor, the enzyme was assayed using a 2 mM concentration of substrate, and it gave a reaction rate of 20 umol/min. What percentage of the...
An uncompetitive inhibitor of an enzyme catalyzed reaction
biochemistryAn uncompetitive inhibitor of an enzyme catalyzed reaction a. binds to the ES complex b. is without effect at saturating substrate concentration. c. can actually increase reaction velocity in rare cases. d. decreases Vmax e. Binds to Es completx and lowers Vmax
The rate of an enzyme-catalyzed reaction initially increases with an increase in the substrate concentration, but eventually reaches a maximum value, even though the concentration of substrate continues to increase. Which of the following best explains why? O As substrate concentration increases, the substrates preferentially bind with each other instead of the active site of the enzyme, and no additional catalysis occurs. As substrate concentration increases, the active sites of all the enzyme molecules become occupied with substrate molecules, and...
Need help with number 13! I already asked about number
12. The inverse velocity and inverse substrate concentration relationship for an enzyme-catalyzed reaction is given below V Vmax Vmax S For the hydration of CO2 catalyzed by carbonic anhydrase, it was determined experimentally that (dm s mol 4023.9+ 39.934 at a total enzyme IS] concentration of 2.32 × 10-y mol-dm- What is the value of the Michaelis constant KM for this enzymatic reaction? (B). 9.92x103 mol dm3 (D). 100.8 mol...
3. The Michaelis-Menten Graph also shows the theoretical maximum rate of the enzyme (Vmax), the point where the enzyme is working at its maximum rate (Vmax/2), and amount of substrate needed to bind half of the active sites (Km). Label these points on the graph. Vmax represents: Vm Vmax/2 represents: Reaction velocity v Vmax 2 Km represents: Kim Substrate concentration (5)
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