Question

-4a 2a Arrhenius equation: k A exp(E/RT Rate Integated Rat Oder Equatisn Plat Sape Ideal gas: pV-nRT; R = 8.314 /K-mol :0.08206 atm_L/mo Xa·m/(ruml: Molarity: M ansowe (mole)/Volume of solu in L; molality m- Foe (mole/mass of solvent (in kg) Part I.Short questions: (56 pt. No explanation is needed.) 1. (4pt) For the second-order reaction below, the initial concentration of reactant A is 0.24 M. f the rate constant for the reaction is 15 x 10 M'st, what is the concentration of A after 265 seconds? (-/At KAP) a) 0.19M b) 0.12Mc) d)5.2M c) 0.95M d) 5.2Me)4.0Mf none of the above. R 2. The reaction C(s)+ H:0(g)H(g)+CO(g) with the enthalpy of reaction AHP 131 k is under equilibrium at 3oo K. How would this reaction system response to each of the following actions in order to re-establish its equilibrium (1) (3pt) removing H:O (g). Note right means products side; left mean reactants side. The system will (shift to left, have no change, or shift to right). (2) (3pt) increasing volume of the container The system will (shift to left, have no change, or shift to right). (3) (3pt) decreasing the temperature. The equilibrium constant of the reaction will (increase, have no change or, decrease). 3. (4pt) What is the balanced equation for the following equilibrium constant expression? a) 6S0-(g)+30-(g)6S0(g) 4. (4pt) in the following reaction, HCO,(ag)+ Hou)Coaq)+HO1aq) a) H30' is an acid and HCO, is its conjugate base. b) HCO)-is an acid and CO-is its conjugate base. c) HCO, is an acid and H:0 is its conjugate base d) H,0 is an acid and CO, is its conjugate base. e) H,0' is an acid and CO, is its conjugate base. 5. The freezing point of pure paradichlorobenzene is 53.0 "C and the freezing point depression constant, Kip, is-7.1 DC/m. Part 1 (4pt) What is the freezing point of a solution containing 2.80 grams benzene (molar mass 78.11g/mcl) dissolved in 43.0 grams paradichlorobenzene (molar mass- 147.0 g/mol)? a)46.7℃ b) 47.1 ℃ c)58.9℃ d) 52.2℃ e) none of the above Part 2 (3pt) Compound XYZ has molar mass 126.13 g/mol. When 2.80-g XYZ dissolved in 43.0 grams paradichlorobenzene, its freezing point should be the freezing point of 2.80 grams benzene diss in 43.0 grams paradichlorobenzene. b) equal to c) less than d) insufficient information a) greater than

Answer 1