Question

clear working please

R1 I1 8 12 13 R2 R3 E1 6. 10 O B Figure 3 Determine; The total resistance seen by the battery. (i) (ii) The current supplied by the battery. The current through R2. (ii) The current through R3. (iv) (v) The Thevenin equivalent circuit. The value of load resistor, to be connected across AB, needed to receive (vi) maximum power from the circuit.

Answer 1

solution RI A- I3 YI2 R NAN 10V OB Total resistance seen by the battery R = R1 + R21183 = R1 + R2 R3 R2TR3 = 82 + 32 x 6 sem 3 +6 = 8r+ 2 2 = lor The current supplied by the battery Il = EL = 10V =TA MAR ION . The current through R2 using current divider formula, we get

= I 2 = b = 2 A I 3 = Iiſ R2 R2 + R3 1 3+6 :) I3 = - 2 A Thevenins equivalent. cirunt the opencirant voltuge Calculate stepli This is the A and B. between the terminats The rinim voltage (th). Open urant voltage = th = 12 R2 = 13R3 - Yth = (2) (3) = 6 (1/2) = 2v =). Vth = 2V step : short voltage source as shown below and calculate the open iran't resistance. This is the Therenin Resistance Crth 8 » R3 61 R2 =-327

Rth - Rit R2 11R3 n = R1 + R2 R3 R2 + R3 = ss +32 x 62 =lor 3+61 Step 3: connect the Rt resister in series With Voltug source (uth as sh Figure below. Rih = lor vth -2V Rth 101 The amount of power dissipated across the load resistor RL is. PL 12R The condition for maximum power dissipation across the load is RL = Rth - RL = Rith = lor