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Question 1 20 pts R3 5 R1 R2 In the circuit 10 15 11 + V1 5 0.5( 12 shown, the current through the dependent source 12 is rel

In this question, use the same circuit as in Question 1, except, make R1 a variable resistor. We are interested in the Theven

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Answer #1

I 2= BIR3 10 is In Vi - 5 ß VB-5 # Solution R3 RI R2 I, os Wise superposition Theorem to find iRz I, = 0.5 Amp open circuit IIs = V8-5 R3 + VB-5 Ritra 5B/VB-10) - VB-5) Apply KCL at node B BT:RE VB-5 + V8-5 R3 Rat Ri V8-5 R3 VB-5 -] (RatRD VB-5-5 VB-VB-0 R3 I + IM VB-5-0 + Ret R2 VB VB-5 R3 (RITR2) Ve-5) _BVB 25 5 5 VB - 58 VB V8-5 + 25 25 RE 11 Iga VB + s I 526-58 16-58 BFor manumum power transfer through. R, as function of ß. For Rth on Voltage source short circuit. current source open circuit

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