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R1 C1 HH The V1 R2 11 R3 circuit shown is a simplified representation of a small signal transistor amplifier circuit. The AC

reference, 1 pF = 1e-12 F, and 1 H = 1e-6 H.) Suppose the operating frequency, f, is 100 MHz. We can find the AC Thevenin equ

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- ei =10 pf f-100x106 Zc= / -) jwe a5fxC. 8 -12. 21 x 10x10x10 L=14F 2e = -3 159.15. 24ufwL =(zacióxió) = Í 628.31.1. R1:50o; 6.283 P6 -3 0.00628 th + 100 in = -50.00159 Uth in (100+; 6.283) -10.00469 Uth. P, 0:00 469 Vith 100+ j 6.283 (2) substitutApply ICL At node A, I, s Iz + I3. 0-1000 in 500 Ź Pb + 1000 in Han v -j159.15 o i 0.00628 v in ( 3+1 6.283 ) (1) Apply KCL a4 * a cool = Rp s 2th 2 load -9.6676 -35.384 2. o 2 Lool 5.-9.6676 -3 5.3842. =) R - .jxc. R=-9.6676 Xc=5.3842 Xcs wc. ca = 2

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