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Your answer is partially correct. Try again. In the figure R1 = 9.54 k2, R2 = 15.2 kq, C = 0.389 UF, and the ideal battery ha

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When switch is closed a long time. then there is no current in capacitor and capasitas has maximum charge. E=21.ov Ri=9.54 krOmax = 5x105 c ©max = 5 ДС then switch is opened at Capacitor will be discharge. (+=o) then In case of dis Charging a at time- t = 4.4 ms - 4.4810 3 (4-4.481035 i= 5x106 15.2x103 x 0.389406 (4.4x10-3 45. 2X103 x 0.389x10-6 i = 0.845 x 10-3 e-(0.1997

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