Please provide answers and explanation for the below problem, thanks.
2 moles 1 mole 1 mole 2 moles
Number of moles of silver nitrate = wt/MW = 3.14 X 10-5 / 170 = 2 X 10-7 moles
Concentration of Silver nitrate = number of moles / volume = 2 X 10-7 / 15 X 10-3 = 1.33 X 10-5 M
Concentration of CrO42- = 6 X 10-5 M
QSP = [Ag+]2 [CrO42- ] = (1.33 X 10-5 )2 (6 X 10-5)
= 10.666 X 10-15
Number of moles of Silver nitrate present are 2 X 10-7
Number of moles of potassium chromate are 6 X 10-5 mol/L (15X 10-3 L) = 9 X 10-7
Precipitate will not be formed because there is no sufficient amount of silver nitrate for the reaction to occur
######## Calculating KSP
The amount of silver nitrate needeed = 18 X 10-7 moles
Molarity of this substance = n/V = 18 X 10-7 / 15 X 10-3 = 1.2 X 10-4 M
Molarity of potassium chromate = 6 X 10-5 M
KSP = [Ag+]2 [CrO42-] = (1.2 X 10-4)2 (6 X 10-5)
= 1.44 X 6 X 10-13
= 8.64 X 10-13 = 0.864 X 10-12
KSP = 0.864e-12
QSP = 10.667e-15
Please provide answers and explanation for the below problem, thanks. A key step in the metabolism...
The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P): G6P F6P K = 0.510, at 298K. Calculate Delta G when Q, the [F6P|/[G6P] ratio, equals 10.0. times 10 J/mol Enter your answer in scientific notation.
Help 17 1 attempts left Check my work Be sure to answer all parts. Ints The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6 phosphate (F6P): G6P FOP K=0.510, at 298K. eBook Calculate AG when Q, the [F6P[G6P] ratio, equals 10.0. Print Report problem References 24.5 xnol N Hint Enter your answer in scientific notation. Solution Guided Solution < Prey 17 of 20 Next > e BE - Type here to...
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔG∘: reaction A:reaction B:glucose-1-phosphatefructose-6-phosphate⟶⟶glucose-6-phosphate,glucose-6-phosphate, ΔG∘=−7.28 kJ/mol ΔG∘=−1.67 kJ/mol Part A Calculate ΔG∘ for the isomerization of glucose-1-phosphate to fructose-6-phosphate. ΔG∘ = -5.61 kJ/mol Part B Calculate the equilibrium constant K for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 K. Express your answer numerically using two significant figures. K = 9.6 Part C Calculate ΔG when the concentration of glucose-1-phosphate is 10 times greater than the concentration...
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔG∘: reaction A:glucose-1-phosphate⟶ glucose-6-phosphate, ΔG∘=−7.28 kJ/mol Reaction B: fructose-6-phosphate⟶⟶glucose-6-phosphate,ΔG∘=−1.67 kJ/mol Calculate the equilibrium constant K for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 K. Express your answer numerically using two significant figures.
calculate delta G urses Carbohydrate Metabolism Problems > 220193 CHEM.3418.01 In-Class Assignments Qui Calculate AGº for the isomerization of glucose-6-phosphate (G6P) to glucose-1-phosphate (G1P). What is the equilibrium ration of glucose-6-phosphate to glucose-1-phosphate at 25°C? The free energy of hydrolysis of G6P is -13.8 kJ/mol and that of G1P is -20.9 kJ/mol. Finish on 1 A- BIELES
7. Determine the ΔG based on the reaction given below. Please show your work for full points and include units for your answer. glucose-6-phosphate isomerase glucose-6-phosphate -----------------→ fructose-6-phosphate ΔG’°= +2.0 kJ / mol 1.4 mM 0.50 mM 8. If glucose-6-phosphate is present at 1.4 mM, what is the maximum concentration of fructose-6-phosphate that may be present and still permit reaction left to right? (Temperature is assumed as a constant of 298 Kelvin)
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Question 1 - Linked Reactions (10 marks) The reaction catalysed by pyruvate kinase is: Phosphoenolpyruvate+ ADPpyruvateATP Keg 3.63 x 105 a) Calculate the AG" for this reaction. Show your working. 3 marks b) The hydrolysis of ATP has following equation: AG 30.5 kJ/mol Calculate the AG" for the following reaction: Phosphoenolpyruvate pyruvateP Show your working. 2 marks c) At 37 °C, the steady-state concentrations of phosphoenolpyruvate, ATP, and ADP have been measured to be 23 HM, 1.85 mM and 140...
please help me find part 2 in this question with explanation. thanks Print Periodic Table Ebook Question 11 of 18 (1 point) X Incorrect X In The rate constant for the reaction of nitrogen with oxygen was determined at four temperatures. Calculate the activation energy and frequency factor A for the reaction given the data below. N, (g) o g) 2 NO (g) T (K) k (cm /molecule s) Number 250 7.18 x 10-8 14.2 kJ mol 275 1.36 x...