![Be sure to answer all parts. The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P): G6P_F6P K = 0.510, at 298K. Calculate AG when Q, the [F6P|/[G6P] ratio, equals 10.0. x10 J/mol Enter your answer in scientific notation.](http://img.homeworklib.com/questions/705c0ba0-649e-11eb-bf2d-bf847dc10f17.png?x-oss-process=image/resize,w_560)
Homework Answers
dG0 = -RT ln K
Putting values:
dG0 = -8.314*298*ln(0.510) = 1668.26 J/mol
Using relation:
dG = dG0 + RT ln Q
Putting values:
dG = 1668.26 + 8.314*298*ln(10) = 7373.08 J = 7.373*103 J/mol
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The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P)...
Please provide answers and explanation for the below problem, thanks. A key step in the metabolism...
Please provide answers and explanation for the below problem,
thanks.
A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6 phosphate (F6P) as shown below. G6P F6P At 298 K, the equilibrium constant for the isomerization is 0.510. (a) Calculate ΔG° at 298 K. (b) Calculate ΔG When Q, the [F6P]/[G6P] ratio, equals 20.0. (c) Calculate ΔG When Q = 0.700. (d) Calculate Q in the cell iAG =-2.50 kJ/mol. kJ/mol kJ/mol...
Help 17 1 attempts left Check my work Be sure to answer all parts. Ints The...
Help 17 1 attempts left Check my work Be sure to answer all parts. Ints The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6 phosphate (F6P): G6P FOP K=0.510, at 298K. eBook Calculate AG when Q, the [F6P[G6P] ratio, equals 10.0. Print Report problem References 24.5 xnol N Hint Enter your answer in scientific notation. Solution Guided Solution < Prey 17 of 20 Next > e BE - Type here to...
14. The second step of glycolysis is the following reaction: Glucose-6-phosphate = Fructose-6-phosphate At pH 7...
14. The second step of glycolysis is the following reaction: Glucose-6-phosphate = Fructose-6-phosphate At pH 7 and 25 °C, IM of G6P and F6P will equilibrate to [F6P]/[G6P] = 2.43. R, the molar gas constant, is 8.3145 Jmol'K'. A) What is the standard free energy of this reaction at pH 7 and 25 °C? (2 points) B) In the cell the overall AG is -1400 Jmol"!. Calculate the ratio of products to reactants. (2 points)
9. One of the important reactions in the biochemical pathway glycolysis is the reaction of glucose-6-phosphate(G6P)...
9. One of the important reactions in the biochemical pathway glycolysis is the reaction of glucose-6-phosphate(G6P) to form fructose-6-phosphate (F6P): a) Is the reaction spontaneous or nonspontaneous under standard state conditions? b) Standard state conditions imply the concentrations of G6P and F6P to be 1 M, however, in a typical cell, they are not even close to these values. Calculate ΔG when the concentrations of G6P and F6P are 120 μM and 28 uM respectively, and discuss the spontaneity of...
The conversion of G6P to fructose-6-phosphate (F6P), catalysed by phosphohexose isomerase (PI), is thermodynamically unfavourable under...
The conversion of G6P to fructose-6-phosphate (F6P), catalysed by phosphohexose isomerase (PI), is thermodynamically unfavourable under standard conditions. AG 1.7 k/mol a) Using the data below calculate the mass action ratio (Q) and the AG at 37°C for each pair of G6P and F6P concentrations. [G6P] (HM) [F6P] (HM) Q AG at 37°O 0.8 3.3 2.1 1.2 2.6 0.1 1.3 2.2 2 marks b) Plot your calculated AG values against the natural log (In) of Q. Remember to clearly label...
Glucose-6-P isomerase catalyses the following glycolytic reaction: Glucose-6-P (G6P) fructose-6-P...
Glucose-6-P isomerase catalyses the following glycolytic reaction: Glucose-6-P (G6P) fructose-6-P G=1700 kJ/mol (Change in free energy) If 7.2 g of G6P* is dissolved in 980 mL of buffer and 150 µL of this is incubated with enzyme at 25°C & 37°C, what would be the equilibrium concentration of F6P at these two temperatures? [15 marks] *- The periodic table may be used to determine the molecular weight of G6P
calculate delta G urses Carbohydrate Metabolism Problems > 220193 CHEM.3418.01 In-Class Assignments Qui Calculate AGº for...
calculate delta G
urses Carbohydrate Metabolism Problems > 220193 CHEM.3418.01 In-Class Assignments Qui Calculate AGº for the isomerization of glucose-6-phosphate (G6P) to glucose-1-phosphate (G1P). What is the equilibrium ration of glucose-6-phosphate to glucose-1-phosphate at 25°C? The free energy of hydrolysis of G6P is -13.8 kJ/mol and that of G1P is -20.9 kJ/mol. Finish on 1 A- BIELES
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy Δ...
Consider the following isomerization reactions of some simple
sugars and values for their standard Gibbs free energy
ΔG∘: reaction A:reaction
B:glucose-1-phosphatefructose-6-phosphate⟶⟶glucose-6-phosphate,glucose-6-phosphate, ΔG∘=−7.28
kJ/mol ΔG∘=−1.67 kJ/mol
Part A
Calculate ΔG∘ for the isomerization of
glucose-1-phosphate to fructose-6-phosphate.
ΔG∘ =
-5.61
kJ/mol
Part B
Calculate the equilibrium constant K for the
isomerization of glucose-1-phosphate to fructose-6-phosphate at 298
K.
Express your answer numerically using two significant
figures.
K =
9.6
Part C
Calculate ΔG when the concentration of
glucose-1-phosphate is 10 times greater than the
concentration...
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔG...
Consider the following isomerization reactions of some simple sugars and values for their standard Gibbs free energy ΔG∘: reaction A:glucose-1-phosphate⟶ glucose-6-phosphate, ΔG∘=−7.28 kJ/mol Reaction B: fructose-6-phosphate⟶⟶glucose-6-phosphate,ΔG∘=−1.67 kJ/mol Calculate the equilibrium constant K for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 K. Express your answer numerically using two significant figures.
The ΔG°′ for the conversion of glucose-1-phosphate (G1P) to glucose-6-phosphate is -7.1 kJ/mol. What is the...
The ΔG°′ for the conversion of glucose-1-phosphate (G1P) to glucose-6-phosphate is -7.1 kJ/mol. What is the ratio of the concentration of G6P to the concentration of G1P that provides a free energy change of –2.0 kJ · mol–1 at 37°C. [Express your answer in decimal form using 2 significant figures.]
Please provide answers and explanation for the below problem,
thanks.
A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6 phosphate (F6P) as shown below. G6P F6P At 298 K, the equilibrium constant for the isomerization is 0.510. (a) Calculate ΔG° at 298 K. (b) Calculate ΔG When Q, the [F6P]/[G6P] ratio, equals 20.0. (c) Calculate ΔG When Q = 0.700. (d) Calculate Q in the cell iAG =-2.50 kJ/mol. kJ/mol kJ/mol...
Help 17 1 attempts left Check my work Be sure to answer all parts. Ints The key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6 phosphate (F6P): G6P FOP K=0.510, at 298K. eBook Calculate AG when Q, the [F6P[G6P] ratio, equals 10.0. Print Report problem References 24.5 xnol N Hint Enter your answer in scientific notation. Solution Guided Solution < Prey 17 of 20 Next > e BE - Type here to...
14. The second step of glycolysis is the following reaction: Glucose-6-phosphate = Fructose-6-phosphate At pH 7 and 25 °C, IM of G6P and F6P will equilibrate to [F6P]/[G6P] = 2.43. R, the molar gas constant, is 8.3145 Jmol'K'. A) What is the standard free energy of this reaction at pH 7 and 25 °C? (2 points) B) In the cell the overall AG is -1400 Jmol"!. Calculate the ratio of products to reactants. (2 points)
9. One of the important reactions in the biochemical pathway glycolysis is the reaction of glucose-6-phosphate(G6P) to form fructose-6-phosphate (F6P): a) Is the reaction spontaneous or nonspontaneous under standard state conditions? b) Standard state conditions imply the concentrations of G6P and F6P to be 1 M, however, in a typical cell, they are not even close to these values. Calculate ΔG when the concentrations of G6P and F6P are 120 μM and 28 uM respectively, and discuss the spontaneity of...
The conversion of G6P to fructose-6-phosphate (F6P), catalysed by phosphohexose isomerase (PI), is thermodynamically unfavourable under standard conditions. AG 1.7 k/mol a) Using the data below calculate the mass action ratio (Q) and the AG at 37°C for each pair of G6P and F6P concentrations. [G6P] (HM) [F6P] (HM) Q AG at 37°O 0.8 3.3 2.1 1.2 2.6 0.1 1.3 2.2 2 marks b) Plot your calculated AG values against the natural log (In) of Q. Remember to clearly label...
calculate delta G
urses Carbohydrate Metabolism Problems > 220193 CHEM.3418.01 In-Class Assignments Qui Calculate AGº for the isomerization of glucose-6-phosphate (G6P) to glucose-1-phosphate (G1P). What is the equilibrium ration of glucose-6-phosphate to glucose-1-phosphate at 25°C? The free energy of hydrolysis of G6P is -13.8 kJ/mol and that of G1P is -20.9 kJ/mol. Finish on 1 A- BIELES
Consider the following isomerization reactions of some simple
sugars and values for their standard Gibbs free energy
ΔG∘: reaction A:reaction
B:glucose-1-phosphatefructose-6-phosphate⟶⟶glucose-6-phosphate,glucose-6-phosphate, ΔG∘=−7.28
kJ/mol ΔG∘=−1.67 kJ/mol
Part A
Calculate ΔG∘ for the isomerization of
glucose-1-phosphate to fructose-6-phosphate.
ΔG∘ =
-5.61
kJ/mol
Part B
Calculate the equilibrium constant K for the
isomerization of glucose-1-phosphate to fructose-6-phosphate at 298
K.
Express your answer numerically using two significant
figures.
K =
9.6
Part C
Calculate ΔG when the concentration of
glucose-1-phosphate is 10 times greater than the
concentration...
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