Question

The acceptable level for insect fith in ten-gram portions of the food item is obtained and results in a sample mean of x 2.5 insect fragments per ten-gram portion below a certain food item is 2 insect fragments (larvae, eggs, body parts, and so on) per 10 grams. A simple random sample of 60 (c) What is the probability a simple random sample of 60 ten-gram portions of the food item results in a mean of at least 2 5 insect fragments? P225(Round to four decimal places as needed ) Is this result unusual? O A. This result is unusual because its probability is large O B. This result is not unusual because its probability is small. O C. This result is not unusual because its probability is large O D. This result is unusual because its probability is small What might we conclude? O A. Since this result is not unusual, it is not reasonable to conclude that the population mean is higher than 2 O B. Since this result is not unusual, it is reasonable to conclude that the population mean is higher than 2 O C. Since this result is unusual, it is reasonable to conclude that the population mean is higher than 2 0 D. Since this result is unusual, t is not reasonable to conclude that the population mean is higher than 2 Click to select your answer(s)

Answer 1

Here, mean = 2

std,dev = sqrt(2/60) = 0.1826

c)

P(x> 2.5)
= P(z > (2.5- 2)/0.1826)
= P(z > 2.7382)
=0.0031

Option D)

Option c)