The solubility of K2Cr2O7 in water is 125 g/L at 20 °C. A solution is prepared...
The solubility of K2Cr2O7 in water is 125 g/L at 20 °C. A solution is prepared at 20 °C that contains 6.0 grams of K2Cr2O7 in 50. mL of water. This solution is ?
I know the answer is unsatrated but can you explain how and how can I calculate it ?
what I did I took the molarity and * by the volume
which is 6.0*0.05 = 0.3
then I took the mole and* by the formula weight which is
0.3*294=88
so the 88 is less than the solibility which is 125
so it will be undersaturated
does my work correct ?
Homework Answers
Apply
the solubility is 125 g/L
then
calcualte concentration of experiment
C = m/V = 6/50 = 0.12 g /mL
change to Liter = 0.12 g / mL * 1000 mL / L = 120 g/L
since 120 < 125, then this is unsaturated
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