Question

Physics 195 - Straight-line kinematics E. Graph 2: Plot instantaneous velocity as a function of time. NOTE: LEAVE W OF THE LEFT SIDE OF THE GRAPH PAPER FREE IN ORDER TO FIND THE INTERCEPT ON THE TIME AXIS (see diagram below). Rewrite your instantaneous velocity values from column (4) in the table below next to their corresponding time values. Remember that you can treat your average velocity data in column (4) as an instantaneous velocity if you remember that the glider has this instantaneous velocity at the middle of the time interval. Thus, your first velocity occurs at 0.05s, and the next is at 0.155, 0.25s, ...etc. Use your values in the table below to plot the instantaneous velocity of the glider as a function of time. Be careful and watch your scale when creating your graph. Remember to leave V of the left side of the graph paper free in order to find the intercept on the time axis (see diagram above). t(s) v (cm/s) 0 = 4y 0.050 0.150 0.250 0.350 0.450 0.550 0.650 0.750 0.850 0.950 1.050 1.150 1.250 1.350

Answer 1

Solution (E) in Plot of instantaneous velocity versus time. 1 Small dinútim a long waris = 0.010s 1 Small division along ganus = langs G (cn/s) HO DO Got got @ @ 20 000 Tot 607 sot @ @ zot O @ oba otrasnolu to be consider the 0.00 0 200 0-300 o yooo-Soo 0600 0700 0.400 0.40 to 100:20, 1:30. ts at tome (H) - Osel Intercept = v(comp) - Il coms