Question

On a bright winter's day, a coach notices an echo as she runs between a high school's playing field and the rear wall of its gym. She decides to estimate how far she stands from the reflective wall. She abruptly whistles and determines that the sound pulse returns to her as an echo 0.431 seconds later (averaging several trials for enhanced reliability). The air is a frigid -10°C. Six months later, the coach decides to repeat her experiment on a hot summer day, standing at the same exact spot. This time, the echo takes a slightly shorter 0.397 seconds to return to the coach. (a) What is the temperature (in °C) of the air on the summer day? °C (b) How far (in m) does the coach stand from the reflective wall? m

Answer 1

al-loc, let velouty of sound is 10 * 3 - 11 - 2.10 whell at summer (°C), T2={t+27336 t2 - - 0 40 N TÍ where I n temperature t+273 Co.431 12 -107273 - 0.397 178 t +273 = 309.98 It=36.98 °C temperature of air on summer=36.98 € Ars cher's Signature ;

from equation (1) distance of coach from reflecting wall, d=2810Xt1 = 2x 325:11 x 0:431 d = 280.24 m/