Question

Java

1. Can you explain it how it will be printed step by step?

Thanks!!

What is printed by the following?

for (int i=1; i<4; i++) { for (char c=’a’; c<=’c’; c++) {

if (i%2==0) { i++; System.out.println(i + " " + c); }

else { c++; System.out.println(c + " " + i);

} } }

2. Is there a compiler error in this code? If so, what is it? If not, what’s printed?

Is there a compiler error in this code? If so, what is it? If not, what’s printed?

1 public class WhatsPrinted10 {

public static void f1() {

System.out.print("a");

}

public static void f2() {

f1();

System.out.print("b");

}

public static void f3() {

f2();

f1();

System.out.print("c");

}

public static void main(String args[]) {

f3();

System.out.println();

}

}

Answer 1

1)The outer loop will run for 4 times

The inner loop will have intial value as 'a' which will be incremented till c becomes 'c' so depending the if condition the statements will be printed the result will be:

2)There is no compilation error in given code everything is fine it will be executed successfully the output will be:

From the main method the call stack will be to f2,f3 and f1 methods which will print the statements as:

abac