Java will be printed 10. can you explain step by step why? public class WhatsPrinted2 { public static void whatHappens(int A[]) { int []B = new int[A.length]; for (int i=0; i<A.length; i++) { B[i]=A[i]*2; } A=B; } public static void main(String args[]) { int A[] = {10,20,30}; whatHappens(A); System.out.println(A[0]); } }
will print 10. explain how it's works. Thanks
public class WhatsPrinted3 { public static int[] whatHappens(int A[]) { int []B = new int[A.length]; for (int i=0; i<A.length; i++) { B[i]=A[i]*2; } return B; } public static void main(String args[]) { int A[] = {10,20,30}; whatHappens(A); System.out.println(A[0]); } }
public class WhatsPrinted4 { public static int[] whatHappens(int A[]) { int C[]=new int[A.length]; for (int i=0; i<A.length; i++) { C[i]=A[i]; } return C; } public static void main(String args[]) { int A[]={10,20,30}; int B[]=whatHappens(A); if (A==B) { System.out.println("equal"); } else { System.out.println("not equal"); } } }
step by step please. thanks
1.
The program prints 10 because array A is passed as value to the function. So whatever changes made to the array A inside the function will not get reflected in main method
=> printing A[0] in main method will give 10 as 10 is the first element in the actual A
A[0] will be 20 inside the whatHappens function
2.
whatHappens function returns B which is not handled by the main function
=> values of B are not getting reflected to A
If A is assigned with B in main function, then 20 will be printed.
3.
array C is assigned with array A's values and returned which is handled by array B.
In if condition, the address of A and B are checked which is different from each other and produces "Not equal" as the output
values have to be compared to check whether both the arrays are equal.
Java will be printed 10. can you explain step by step why? public class WhatsPrinted2 {...
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