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Data is for P 1 bar and 25C AH (kJ mol) NAg) H,(g) NH (g) S (J K mol ) 191.5 130.6 192.3 46.1 13) 812. (a) Calculate &G for

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Answer – We are given standard enthalpy and entropy of each in given reaction and need to calculate the standard free energy for the reaction at temperature 25oC –

N2(g) + 3 H2(g) <-----> 2 NH3(g)

ΔHorxn= ∑ ΔHof of product – ∑ ΔHof of reactant

= [ 2* ΔHof NH3(g)] – [ΔHof N2(g) + 3*ΔHof H2(g)]

= (2*46.1) – ( 0.00 + 3*0.00)

= 92.2 kJ/mol

ΔSorxn= ∑ ΔSof of product – ∑ ΔSof of reactant

= [ 2* ΔSof NH3(g)] – [ΔSof N2(g) + 3*ΔSof H2(g)]

= (2*192.3) – ( 191.5 + 3*130.6)

= -200.7 J/mol.K

we know formula for standard free energy

ΔGorxn= ΔHorxn -T ΔSorxn

            = 92.2 kJ/mol – 298K * (-0.2007 kJ/mol.K)

             = 152.0 kJ/mol

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