Homework Answers
The reduction potential for Ag+ is more than that of Zn2+,so Ag+ is reduced at cathode and Zn is oxidised at anode.
Eocell= Eocathode- Eoanode
= EoAg+/Ag - Eo Zn2+/Zn
= +0.80-(-0.76) V
= +1.56 V
So all the given statements are correct.
Therefore option D is correct
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reaction?______
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