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Took too long, please do not answer and credit my question back ..... Consider equal mass...

Took too long, please do not answer and credit my question back ..... Consider equal mass of samples of several metals that absorb heat from their surroundings so their temperature increases from 295K to 345K. Which metal needs to absorb the smallest amount of heat to reach 345K?

Al

Mg

Ni

Li

Pb

science   chemistry   
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Answer #1

heat absorbed by metal = mass of metal x specific heat x rise in temperature

As all metals have equal mass and the rise in temperature also same,

the heat needed is proportional to its specific heat.

Thus the metal with lowest specific heat is the one which requires smallest heat to reach 345K.

Let us compare the specific heats.

metal specific heat

Al 0.92J/g.K

Mg1.0467 J/g.K

Li 3.55J/g.K

Ni 0.502J/g.K

Pb 0.125 J/g.K

Thus lead ,Pb being the with lowest specific heat , it is the metal that needs smallest heat to rise the temperature.

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