vy is constant
a) after time t in y direcction r= vy*t = 8t j
x direction S = 0.5*a*t*t = 0.5t2 i
so r(t) = 0.5t2i + 8t j
b) velocity = 8j+ati
=8j+t i
c) at t = 3
r(3) = 0.5*3*3i+8*3j so cordinates = (4.5,24)
d) distance from origin at t=3
= sqrt(4.5*4.5+24*24) = 24.42
so speed = 24.42/3 m/s = 8.14m/s
position vector = 8t i + 0.5*t2 j
velocity = 8i + tj
net velocity = (8^2 + t^2)^0.5
(c) 24i + 4.5j
(d) 8i+ 3j
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