The equilibrium constant, K, for the following reaction is 3.78×10-2 at 530 K. PCl5(g) PCl3(g) +...
The equilibrium constant, K, for the following reaction is 3.78×10-2 at 530 K.
PCl5(g) PCl3(g) + Cl2(g)
An equilibrium mixture of the three gases in a 5.47 L container at 530 K contains 0.295 M PCl5, 0.106 M PCl3 and 0.106 M Cl2.
What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 12.1 L?
[PCl5] = M
[PCl3] = M
[Cl2] = M
please help me!
I don't understand how you rearrange to get an expression of the form ax2+bx+c=0 and use the quadratic formula to solve for x. I have been struggle on this part. please help me to understand.
Homework Answers
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The equilibrium constant, K, for the following reaction is
3.78×10-2 at 530 K.
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