Question

Part B How many grams of ice at -25.4 °C can be completely converted to liquid at 7.2 °C if the available heat for this process is 4.18*103 kJ? For ice, use a specific heat of 2.01 J/(g·°C) and ΔHfus 6.01kJ/mol. Express your answer to three significant figures and include the appropriate units Hints alue Units Submit My Answers Give Up

Answer 1

Q = mc∆T

Q = heat energy (Joules, J), m = mass of a substance (kg)

c = specific heat (units J/kg∙K), ∆ is a symbol meaning "the change in"

∆T = change in temperature (Kelvins, K)

Let us have m is mass of ice

4180 = m x 2.01 x 25.4 + m x 6010 /18 + m x 4.184 x 7.2

4180 = 51.054 m + 333.88m + 30.1248 m

4180 = 415.067 m

mass of ice = 10.07 gm