Question

Software can generate samples from (almost) exactly Normal distributions. Here is a random sample of size 5 from the Normal distribution with mean 8 and standard deviation 2: 4.47 5.51 8.1 11.63 7.91 Although we know the true value of μ suppose we pretend that we do not and we test the hypotheses Ho : μ-5.6 a:μ 5.6 at the α 0.05 significance level. What is the power of the test against the alternative μ 8 (the actual population mean)? Power (+0.0001)

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Solution:

Number of cases 5 To find the mean, add all of the observations and divide by 5 Mean 7.524 H0: H 5.6 HA: μ# 5.6 Sample mean- 7.524 Standard deviation 2.7 Standard error of mean s/n Standard error of mean 2/5 SE 2/2.2361-0.8944 Standard error of mean 0.8944 z - (xbar- H) SE z-(7.524-5.6)/0.8944 z-2.151 alpha 0.0:5 P(z > 2.151) 0.0315 (2-tailed test p-value) Conclusion : Reject the nul hypothesis

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