Question

Suppose 16.6 g of lead(II) acetate is dissolved in 350 mL of a 0.20 Maqueous solution of ammonium sulfate, Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the lead(II) acetate is dissolved in Be sure your answer has the correct number of significant digits.

Answer 1

let tongide a seaction, PbLCgcoo2 Caa) + (NHy)29a4-Pb0+2c CooN aivem data mass of load acatato e 16.69 mass lead (1)aatata mole o molas mass 16.69 32S1288 FLOM gaaction, moles oh aotate ion 2Y mole of laadao 2YO OSTO 0.L020mo Molosity mole) oautate ion Volume ok Sluton Olo2 mo 3s0x103 L Oil02mo) O 3SOL 0.291 mollL Mobity0129 IM