Question

please help quick, please, please, please

2. (a) Illustrate how to convert AG=-RT in Ked to an expression for AG that uses log to the base ten instead of base "e". (b) Show that the expression you've just obtained can be converted to AG in units of kcal/mol) --1.36 log Keq when T = 298 K. [NOTE: I find it very convenient to use -1.4 log Ked to simplify the arithmetic and allow one to carry out some calculations without resorting to use of a calculator.)

Answer 1

A G= RT In keer Inx= 2.303 logio x & & in x the values az 29 8 303 log kear 36kcal food) og Rey Putting the values R = 1.987 callmol-k. 4G = -1.9874298 x 2.303 log keq = -1363-66 (cal Pollogkeq = -1.36 kcal food) og Rea