A converging mirror has a focal length of 3 m. Where should a candle be placed...
A candle is placed 0.550m in front of a converging lens. The image of the object is focused on a screen 0.646m behind the lens. What is the focal length of the lens? What is the magnification of the image? (if the image is inverted, the magnification should be negative)
A candle is placed 1.260m in front of a converging lens. The image of the object is focused on a screen 0.772m behind the lens. What is the focal length of the lens? What is the magnification of the image? (if the image is inverted, the magnification should be negative)
A small object is placed 25.0 cm from a converging lens of focal length 40.0 cm. The object is to the left of the lens. Where is the image? A- 17cm to the right of the lens B- 25cm to the left of the lens C- 17 cm to the left of the lens D-25 cm to the right of the lens E-67cm to the right of the lens F-67 cm to the left of the lens A small object...
(a) Find the focal length of a concave mirror if an object
placed 40 cm in front of the mirror has a real image 80 cm from the
the mirror.
(b) Where will the image be if the object is moved to a point 20
cm from the mirror?
(c) What type will this image be?
(a) Find the focal length of a concave mirror if an object placed 40 cm in front of the mirror has a real image...
A converging lens with a focal length of 20cm is placed between a lighted candle and a white wall that is 100cm from the candle. A sharp image of the candle is visible on the wall. How far from the wall is the lens? There are two correct answers and you should give both of them.
A spherical lens with a focal length of 75 cm is sitting 30 cm to the left of a spherical mirror that has a focal length of −200 cm. A candle is then placed to the left of the lens so that the focal point of the lens is midway between the object and its vertex. (a) Find the object and image distance for the mirror. p2 = ?cm q2 = ?cm (b) Describe the image produced by the mirror....
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
a convex mirror has a focal length of magnitude f. an object is placed in front of this mirror at a point 2/3f from the face of the mirror. the image will appear? A. inverted and enlarged B. behind the mirror C. upright and enlarged D. inverted and reduced E. upright and reduced
Where must an object be placed with respect to a converging lens of focal length of 24 cm if the image is to be virtual, erected, and three times as large as the object? (Note: express your result in cm). Draw the ray diagram to indicate the position of the object and the position of the image with respect to the lens. Show steps.
An object is placed 24.1 cm in front of a convex mirror of focal length 50 cm. Note: Do convex mirrors have a positive or negative focal length? What is its image position? Answer in units of cm. The magnification of the image in the previ- ous question is: With the arrangement discussed above, the image is: 1. virtual, inverted, smaller than object 2. real, erect, smaller than object 3. real, inverted, bigger than object 4. real, erect, bigger than...