Given data,
For wall : Transmission loss (TL1) = 75 dB , A1 = 50 m2 ,
For window : Transmission loss (TL2) = 40 dB , A2 = 10 m2 ,
(i) TL when window closed
transmission coefficient of wall and window
As we know the relation between TL and transmission coefficient ()
For wall: TL1 = 10*log(1/1)
75 = 10*log(1/1)
1 = 0.00055
For window: TL2 = 10*log(1/2)
40 = 10*log(1/2)
2 = 0.01832
Now, Average transmission coefficient ()
= ( A1 *1 + A2 * 2 )/ ( A1 + A2 )
= ( 50 *0.00055 + 10 * 0.01832 )/ ( 50 + 10 )
= 0.00351
Now, TL
TL = 10*log(1/) = 10*log(1/0.00351)
= 24.5 dB
(ii) TL when window opened
Now, Average transmission coefficient ()
= ( A1 *1 + A2 * 2 )/ A1
= ( 50 *0.00055 + 10 * 0.01832 )/ 50
= 0.00421
Now, TL
TL = 10*log(1/) = 10*log(1/0.00421)
= 23.7 dB
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