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A wall has total surface area of 100 m’and consists of three distinct sections with thermal resistance values as follows: Sec

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For part C: On section B if we apply insulation, heat loss will be reduced greatly.

from the given data : - for DT = 10 c. Heat loss A DT Rsi A = Area. Total Heat loss = 60x10 + IOXID 1.06 + 30X10 2.82 4.58 wa

if insulation is fined on Section - B. Too + 300 2082 ㅋ Total heat heat loss 4.58 2.06 9 = 285.93 Woctt. if insulation is fin

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