To what temperature would you have to heat a brass rod for it to be 2.4 % longer than it is at 25 ∘C?
Express your answer to two significant figures and include the appropriate units.
Change in length, dL = L a dT
0.024 = (18.7 x 10^-6) x (T - 25)
Temperature, T = 1308.42 °C
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To what temperature would you have to heat a brass rod for it to be 2.4...
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