Suppose after charging a 3.1 µF capacitor to 14 V, you connect it to another already...
Suppose after charging a 3.1 µF capacitor to 14 V, you connect it to another already charged capacitor of 6.2 µF and 5 V. What voltage will your voltmeter read across those two capacitors connected in parallel?
Homework Answers
Q1 = C1V1 = 3.1 x 14 = 43.4 uC
Q2 = C2V2 = 6.2 x 5 = 31 uC
total charge = 31 + 43.4 = 74.4 uC
net capacitance = 6.2 + 3.1 = 9.3 uF
potential = 74.4/9.3 = 8 V
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