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6. Use a splitting tree to predict the shape and relative heights of the alkene HB multiplet. For reference: Менс JAB = 6 Hz;

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Hb has 2 non equivalent neighbouring protons, Ha and Hc. The J for Hbc is 15 Hz and J for Hab is 6 Hz. Hb will be split into a doublet by Hc. This doublet will again be split into a doublet by Ha. So the final split pattern will be doublet of a doublet.

When a doublet signal is observed, the height of each split peak is equal. So the doublet of a doublet will give a split with 4 peaks of equal height.

On case of Hc, first split will be doublet due to Hb. This doublet will be further split by 3 Hd protons. So ideally the split will be triplet of a doublet. Some of the peaks of this split will overlap. So, a clean triplet of a doublet may Split tree for Ho Joc Split tree for He - Ige+ Icpt 21 not be visible.

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