5. A motorcycle accelerates uniformly from rest and reaches a linear speed of 23.8 m/s in a time of 8.10 s. The radius of each tire is 0.270 m. What is the magnitude of the angular acceleration of each tire?
here,
v = 23.8 m/s
u = 0 m/s
Using First equation of motion ,
v = u + at
23.8 = 8.10 * a
a = 2.94 m/s^2
Now,
as angular acceleration = a/r
angular acceleration = 2.94 / 0.270
angular acceleration = 10.89 rad/s^2
angular acceleration of each tire is 10.89 rad/s^2
acceleration =change in speed/time =23.8/8.10 = 2.938 m/s
angular acceleration = acceleration/radius = 2.938/0.27 = 10.88 rad/sec2
5. A motorcycle accelerates uniformly from rest and reaches a linear speed of 23.8 m/s in...
17.) A motorcycle accelerates uniformly from rest and reaches a linear speed of 21.6 m/s in a time of 9.72 s. The radius of each tire is 0.298 m. What is the magnitude of the angular acceleration of each tire? rad/s2
A car accelerates uniformly from rest and reaches a speed of 22.0 m/s in 9.00 s. Assuming the diameter of a tire is 58.0 cm, (a) find the number of revolutions the tire makes during this motion, assuming no slipping occurs, (b) What is the final angular speed of a tire in revolutions per second?
A car accelerates uniformly from rest and reaches a speed of 22.4 m/s in 8.99 s. Assume the diameter of a tire is 57.1 cm. (a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. rev (b) What is the final angular speed of a tire in revolutions per second?
A car accelerates uniformly from rest and reaches a speed of 21.2 m/s in 8.90 s. Assume the diameter of a tire is 57.9 cm. (a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. rev (b) What is the final angular speed of a tire in revolutions per second? rev/s
001 10.0 points A car accelerates uniformly from rest and reaches a speed of 25.5 m/s in 8.7 s. The diameter of a tire is 83.6 cm. Find the number of revolutions the tire makes during this motion, assuming no slip- ping. Answer in units of rev. 002 10.0 points A figure skater begins spinning counterclock- wise at an angular speed of 3.6 π rad/s. Dur- ing a 5.0 s interval, she slowly pulls her arms inward and finally spins...
001 10.0 points A car accelerates uniformly from rest and reaches a speed of 15.6 m/s in 4.5 s. The diameter of a tire is 35.6 cm. Find the number of revolutions the tire makes during this motion, assuming no slip- ping. Answer in units of rev. 002 10.0 points A figure skater begins spinning counterclock- wise at an angular speed of 4.2 π rad/s. Dur- ing a 4.6 s interval, she slowly pulls her arms inward and finally spins...
A car accelerates uniformly from rest and reaches a speed of 17.8 m/s in 7.1 s. The diameter of a tire is 69.7 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev
a car accelerates uniformly from rest to a speed of 16.5 m/s
in 8.9 s. the diameter of the tire is 70.5 cm. find the number of
revolutions the tide makes during the motion, assuming no
sloping
A car accelerates rest and reaches a speed of 16.5 m/s in 8.9 s. The diameter of a tire is 70.5 cm uniformly from Find the number of revolutions the tire makes during this motion, assuming no slip- ping. Answer in units of...
001 10.0 points A car accelerates uniformly from rest and reaches a speed of 14.9 m/s in 11.5 s. The diameter of a tire is 71.3 cm. Find the number of revolutions the tire makes during this motion, assuming no slip- ping. Answer in units of rev.
001 10.0 points A car accelerates uniformly from rest and reaches a speed of 17.4 m/s in 14.1 s. The diameter of a tire is 85.4 cm. Find the number of revolutions the tire makes during this motion, assuming no slip- ping Answer in units of rev.