5' TCA ACG GAC TGT CTC GTG GAG 3'
Coding strand sequence is,
5' ATC GCT GTG CTC CAC GAG ACA GTC CGT TGA 3'
Now, the complementary sequence of the coding strand will be the
sequence of the primer. So, the complementary sequence of the
coding strand is:
3' TAG CGA CAC GAG GTG CTC TGT CAG GCA ACT 5'
Now, if you arrange in 5' to 3' orientation, then the sequence will
be,
5' TCA ACG GAC TGT CTC GTG GAG CAC AGC GAT 3'
Question 19 (1 point) Saved Forward Primer: GTG ATG CGG GTT TGT GCA GAC (5' to...
Question 19 (1 point) Forward Primer: GTG ATG CGG GTT TGT GCA GAC (5' to 3' on coding strand) Make a reverse primer from the following sequence, also from the coding strand, that is GC clamped and the Tm is within plus or minus 1 degree C (using the rule of thumb for calculating Tm we used in class). Please write the primer in its own 5' to 3' sequence, so we can send it out to be synthesized. ATC...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui ead in onder to. start and stop mak Land when to stot C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand and ONLY start on AUG and STOP when it tells you to stop Follow example below Example: DNA AGA CGG TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC UCU GCC...
please help with #4 and #5
question 5 of 5
the cross lines indicate deletion of the nucleotides.
what type of mutation is this? what is the resulting polypeptide
sequence?
3'- GTT - TAC - CTT - -CTC--TCC -TCA -GAC - ATC -GCA
-5' (template strand)
5' - CAA - ATG - GAA - -GAG--AGG - AGT - CTG- TAG -
CGT - 3' (non-template/coding strand)
answer: It's a ___________________mutation.
Final polypeptide sequence is N' - Met - GLU
_______________ ...
Adenosine deaminases modify adenosines to form
_____________________, which is then read as
_________________________ by the translation and splicing systems,
as well as by reverse transcriptase.
Cephalopods like squid and octopus use this form of editing very
extensively in their protein-coding regions. For each of
the following, please indicate how these enzymes can alter the mRNA
to produce the indicated codon changes.
I (Ileu) is changed to V (val):
K (Lys) is changed to E (Glu):
T (Thr) is changed to A (ala):...
all please
Question 2 (1 point) ✓ Saved In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (v+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v)...