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If 0.696 mol PCl5 is placed in a 1.78 L flask and allowed to reach equilibrium...

If 0.696 mol PCl5 is placed in a 1.78 L flask and allowed to reach equilibrium at a given temperature, what is the final concentration of Cl2 in the flask?

PCl5(g) mc032-1.jpg PCl3(aq) + Cl2(g) Kc = 0.47


a. 0.429 M
b. 0.243 M
c. 0.254 M
d. 0.275 M
e. 0.724 M
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Answer #1

O 698 mol c :696 = o.39午 RIS 은 pel3 +ch O.392 0.392-1 ) [0.3唯一*) o, 41ユ 2 LO, 39-1 (04710, 311-%) 二 Cy 0.254 M [cLJ

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