Question

Airline passengers arrive randomly and

independently at the passenger-screening facility at Sea-Tac Airport. The mean arrival rate is 10

passengers per minute. How is this experiment distributed?

a. Poisson

b. Binomial

c. Exponential

d. It does not have a specific form

24. What is the lambda (λ) for this distribution?

a. 5

b. 10

c. 15

d. 20

25. What is the probability of no arrivals in a one-minute period?

a. 0.0000454

b. 0.0006278

c. 0.0072816

d. 0.0123785

26. What is the probability that fewer than 4 passengers arrive in a one-minute period?

a. 0.0889

b. 0.0613

c. 0.0532

d. 0.0103

27. If we look at the number of passengers in a 15 second period, what is the lambda (λ) now?

a. 10

b. 7.5

c. 5

d. 2.5

28. What is the probability that no passengers arrive in a 15 second period?

a. 0.0415

b. 0.0662

c. 0.0821

d. 0.1013

29. What is the probability of at least one passenger arrives in a 15 second period?

a. 0.3562

b. 0.5627

c. 0.7921

d. 0.9179

Answer 1

1)

a. Poisson

24) λ =    10
25) P ( X =    0   ) = e^-10*10^0/0!=   0.0000454

26) P(X<3) = P(X=0) + P(X=1) + P(x=2) + P(X=3) = 0.0103

27) λ = 10/60*15 = 2.5

28) P ( X =    0   ) = e^-2.5*2.5^0/0!=   0.0821

29) P(X≥1) = 1 - P(X=0) = 1-0.0821 = 0.9179