Question

Please show all the clearly step

A 500 MVA, 24 kV, 60 Hz three-phase synchronous generator is operating at rated voltage and frequency with a terminal power factor of 0.8 lagging. The synchronous reactance X 0.8. Stator coil resistance is negligible. The internally generated voltage E,-18 kv a) Draw the per phase equivalent circuit. b) Determine the torque (power) angle 5, c) the total output power, d) the line current.

Answer 1

Ansa Line Terminal Voltage, V = 24 kV per-phase terminal voltage, Von= V1 = 24 = 13.856 KV Internally generuted voltage, Ep=18 KV Synchronous reactance, Xs=2082 Synchronous Generator Resistance, Ra=0 Terminal Power factor, Cose 2018 I joor om jXs E = 18 Ky ♡ Von = 13.856 KV 60Hz Per-phase Equivalent circut

By On Syndromes eventer, Ees = kako° +420XX) for a Symohamowe Greator, 181 - cup +IR.) +(usuát Ixi 18000*= (13856x0+8+0)2+(1385640.6+I_Koogje ( Cosp=0.8, then Sing=066) 18008 = {13856x08)+(1385660:6+ 0.8.IL JÍ >> 058I4 = J18oo? (3856x0.83€ – (13856x0-6) = 5868.33 I[= 5868.33 = 733541 A. 0.8 et EZS = 1385620° +67335.412-36-86°) (108) (*°=605'(0-8) = 36.80) = 18000 215.12° V • E28=. 18000 215.12 v & Power of Tosque angle, (5= 1512 /

(c) Total output Power, Put = 53 VL IL Cose Put = 53x(@uxló)x(7335.41)XO-8 out = 243.941xlo W = 243.941 MW 0 Total output Power (w = 243,94 HW] Out out (d) Line current Is as calculated in (a) part is given by Line current, I = 7335.41 A
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