Question

Compute the K, X ray energies of calcium calcium zirconium mercury Z-20), zirconium Z-40), and mercury Z-80 Give your answers to at least three significant figures. kev kev keV Compare with the measured values of 3.69 kev, 15.8 keV, and 70.8 keV. (Select all that apply.) The values computed are larger than the measured values. □ The values computed are smaller than the measured values The values computed are all within 5% of the measured values. The error of computed values decreases with larger Z. The error of computed values increases with larger Z.

Answer 1

The expression of energy of the hydrogen electron states for atom of any atomic number Z. E = 13.6 z^2 [1/n^2_1 - 1/n^2_2] ev For calcium Z = 20 E = -13.6 (20)^2 [1/2^2 - 1/1^2]ev E = -5440 [1/4 - 1/1] ev E = - 5440 [1 - 4/4] ev E = - 5440 times - 3/4 ev E = 1360 times 3 ev E = 4080 ev calcium E = 4.080 Kev for Zirconium Z = 40 E = -13.6 (40)^2 [1/2^2 - 1/1] ev E = -21760 [1 - 4/4] ev E = -21760 times - 3/4 ev E = 5440 times 3 ev E = 16320 ev Zirconium E = 16.320 kev \r\n For mercury Z = 80 E = -13.6 (80)^2 [1/2^2 - 1/1^2] ev E = -87040 [1 - 4/4] ev E = -87040 times - 3/4 ev E = -21760 times - 3 E = 65280 ev E Mercury = 65.280 kev Error in value