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A mass m hangs from string wrapped around a pulley of radius R. The pulley has...

A mass m hangs from string wrapped around a pulley of radius R. The pulley has a moment of inertia I and its pivot is frictionless.

Because of gravity, the mass falls and the pulley rotates. The magnitude of the torque on the pulley is..

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equal to mgR
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greater than mgR
less than mgR
0 0
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Answer #1

The equation of motion of the mass is, mg-T = ma = m(g-a) The torque on the pulley is, T=TR = m(g-a)R = mgR-mar = Thus, from

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