Rg = 50ohm
Max power is transferred when load is complex conjugate of
system resistance
Therefore for Load Impedance,Zl = 50 -
j*(2*pi*2.5*10^3*5*10^-3)
=> 50 - 78.54 j
Resistance in Load,R = 50 ohm
Capacitance in Load,C = 8.106*10^-7 F = 0.8106 micro
Farad
Rg = 50ohm Max power is transferred when load is complex conjugate of system resistance Therefore...
answer Q5/// The maximum power dissipated in a 4 load is 100 w when connected to a d.c. voltage V and internal resistance R. Calculate: the current in the load, internal * .resistance R, and voltage V 4 A, 3 Ohm, 30 v o 3 A, 5 Ohm, 12 v 0 2 A, 6 ohm, 24v O 6 A, 2.5 ohm, 220 v O 5 A, 4 Ohm, 40 v O 10 A 4.5 ohm. 60v 0
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