3. Describe how Ecell is related to K (equilibrium constant) and G.
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The equilibrium constant, K, for a redox reaction is related to the standard potential, E∘, by the equation lnK=nFE∘RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e−) , R (the gas constant) is equal to 8.314 J/(mol⋅K) , and T is the Kelvin temperature. Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 5.51×10−3.
The equilibrium constant, K, for a redox reaction is related to the standard potential, Eº, by the equation In K = nFE° RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol · K), and T is the Kelvin temperature. Standard reduction potentials Reduction half-reaction E° (V) Ag+ (aq) + e +Ag(s) 0.80 Cu²+ (aq) + 2e + Cu(s) 0.34...
Relationship between Ecell and K The equilibrium constant for a cell reaction can be calculated from the standard cell voltage. The relationship between them is: RT nF where E standard cell potential R ideal gas constant Tkelvin temperature n number of moles of electrons for the reaction as written Fcharge carried by 1 mol of electrons Kequilibrium constant it is cusomary to use the equation in a form where numerical values are substituted for R., T and F at a...
Calculate the equilibrium constant K for the reactions at 298 K. a) Br2(g) + 2Cl-(aq) ---> 2Br-(aq) + Cl2(g) b) A Galvanic Cell with the SHE and Fe+2/Fe(s)
The reaction A(g)⇌2B(g) has an equilibrium constant of K = 0.040. What is the equilibrium constant for the reaction B(g)⇌12A(g)?
6) Calculate the equilibrium constant K at 25°C for the the equilibrium constant K at 25°C for the following reaction for the standard cell potential: (points) (AFE-R7 In K, F-96485 Címol,R-8.37 J/molk) Pb2+ (aq) + Fe(s) S Pb(s) + Fe?*(aq) 7) Calculate the cell potential of the following cell at 25°C. (7 points) Fe(s)| Fe?"(aq) (1.1 M) || Cu?"(aq) (0.50 M) Cu(3) Ecall-E Call - 0.0592/n logo
13) The value of the equilibrium constant K, for the formation of ammonia, N, (g) + 3 H, () € 2 NH, (e) is 4.75 x 10 at 450 K. What is the K, for the following reaction 2 N N(g) + 3 H; (@)
The reaction A(g)⇌2B(g) has an equilibrium constant of K = 0.010. What is the equilibrium constant for the reaction B(g)⇌12A(g)? Express your answer using two significant figures.
Review I Constants I Periodic Table The equilibrium constant, K, for a redox reaction is related to the standard potential, E°, by the equation Standard reduction potentials nFE RT In K E° (V) Reduction half-reaction Agt(aq)eAg(s) Cu2+(aq)2eCu(s) 0.80 where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol - K) , and T is the Kelvin temperature. 0.34 Sn4t (aq)4eSn(s) 0.15...
The equilibrium constant, K. for a redox reaction is related to the standard potential, E, by the equation Fe(s) + Ni+ (aq) +Fe?+ (aq) + NI(s) FE In K = Express your answer numerically. View Available Hints) where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mole). R (the gas constant) is equal to 8.314 J/(mol-K). and T is the Kelvin temperature. ΟΙ ΑΣΦ h ? KK- Submit Previous Answers *...