Osmotic pressure is a colligative property which will depend upon number of moles of solute as
osmotic pressure = concentration X R X T
Osmotic pressure = 0.75
concentration = Moles of solute / Volume of solution
= 0.0821 L atm / K mole
T = Temperature = 298 K
Concentration = P / RT = 0.75 / 0.0821 X 298 = 0.0306
0.0606 = Moles / 1 L
Moles = 0.0306
Mass / Mol wt = Mole = 0.0306 = 6g / Mol wt
Mol wt = 6 / 0.0306 = 196.07 g / mole
I do not know even the formula for this problem A solution is prepared by dissolving...
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