Question

6. Determine the vant Hoff factor for each of the compounds listed below: a. Glucose (C6H1206) b. calcium phosphate C. Ammonplease answer thank you

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Answer #1

a)

C6H12O6 is a non electrolyte.

So, it will not dissociate

Hence Van’t Hoff factor would be 1

Answer: 1

b)

Calcium phosphate is Ca3(PO4)2

It dissociate into 3 Ca2+ ion and 2 PO43- ions.

So, there are total of 5 particles.

Hence Van’t Hoff factor would be 5

Answer: 5

c)

Ammonium carbonate is (NH4)2CO3

It dissociate into 2 NH4+ ion and 1 CO32- ions.

So, there are total of 3 particles.

Hence Van’t Hoff factor would be 3

Answer: 3

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