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You need to use your cell phone, which broadcasts an 970 MHz signal, but you're behind...

You need to use your cell phone, which broadcasts an 970 MHz signal, but you're behind two massive, radio-wave-absorbing buildings that have only a 17 m space between them. What is the angular width of the electromagnetic wave after it emerges from between the buildings?

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Answer #1

thetamin = arcsine (wavelength / width of slit) = arcsine (speed of light / (frequency * width of slit) )

=(3*10^8/(970*10^6*17))

= 0.0182 That is the angle between the central max and the first minimum. So I suppose if you want the total width of that first hump, double it I.e= 0.0364

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