Many cell phones broadcast their signals at 800 MHz. Imagine you are behind 2 large, radio-wave-absorbing building with only a 13 m space between them. What is the angular distance, in degrees, of the radio wave after it emerges from between the buildings?
thetamin = arcsine (wavelength / width of slit)
= arcsine (speed of light / (frequency * width of slit) )
= sin^(-1)(3*10^8/(800*10^6 * 13))
= sin^(-1)(0.0289)
= 1.6530
That is the angle between the central max and the first minimum
Many cell phones broadcast their signals at 800 MHz. Imagine you are behind 2 large, radio-wave-absorbing...
please answer the following questions
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